CASE – 1: When we are given the positions of the alphabets from left as well as from right in the alphabet series
Sometimes, the problem is to find out the alphabet which is in middle of two given positions i.e. from left and right. To the position given from right, add a particular number x so that the sum table is 27. Now, add that particular number x to position from left. The sum total now around is divided by 2 to find out the position of alphabet, which is in middle of two given position
When the sum of position of two alphabets is 27, then these two words are opposite to each other in the series. A is the first letter and Z is its opposite in the series. Their respective position is 1 and 26. The sum of their position is 1 + 26 = 27. As such both these letters are opposite to each other in the alphabet.
Following are the examples to find out the middle position of two alphabets:
Ex 16: 4th from right and 7th from left?
Ans 16: We are required to find out the letter, which is in between 4th from right and 23rd from left side. The letter which is 4th from right is 27-4=23rd from left. If we add both left positions, we get 23+7= 30 and dividing it by 2, the resultant is 15. And the 15th letter of the alphabet is ‘O’ is the answer.
Ex 17: 17th from left and 6th from right?
Ans 17: We are required to find out the ‘middle’ letter between the 17th alphabet from left and the 6th alphabet from right. The letter, which is 6th from right is 27-6= 21th from left. Adding both the left hand side positions we get 17+21=38 and when we divide 38 by 2, the answer is 19.
Ex 18: 22nd from left and 11th from right?
Ans 18: We are required to find out the ‘middle’ letter between the 22nd alphabet from left and the 11th alphabet from right. The letter, which is 11th from right is 27-11= 16th from left. Adding both the left hand side positions we get 22+16=38 and when we divide 38 by 2, the answer is 19, and the 19th letter in the alphabet is ‘S’.
Ex 19: 3rd from right and 18th from left?
Ans 19: The letter which is 3rd from right side in the alphabet series is 27-3=24th from left side. The other alphabet is 18th from left side and when we add both the left side positions, we get 18+24=42. Dividing 42 by 2, we get 21. The 21st letter is ‘U’ is the answer.
Ex 20: 14th from the right and 19th from the left?
Ans 20: Similarly, the answer will be 16th letter i.e. ‘P’.
CASE – 2: When we are given only two alphabets
Some times we are given simply two alphabets then as we know the place values of these two alphabets, we simply add the place values of these alphabets and then divide the result by 2 to get the answer i.e. the middle position of the alphabets.
Following are the examples to find out the middle position of two alphabets in this case:
Ex 21: Which is the middle letter between H and N?
Ex 22: Which is the middle letter between H and S?
CASE – 3: When we are given the position of two alphabets from R.H.S.
In this case, we simply added the place values of alphabets and then divide the result by 2 as such in case 2. But here the answer we now get that is from R.H.S, but we need the answer from L.H.S. So, according to the rule 1, we simply subtract the above answer from 27 to get the answer from L.H.S.
Ex 23: 10th from right and 4th from right
Ans 23: 10th from right and 4th from right, add both the positions, 10+4= 14 and divide it by 2= 7. The 7th letter from right is 27-7= 20 th from left, so ‘T’ is the answer.
Ex 24: 20th from right and 4th from right
Ans 24: Adding both positions from right i.e. 20th and 4th from right, we get 24and dividing it by 2, we get 12. The 12th letter from right side is 27-12=15th from left side of the alphabet and the said letter is ‘O’.
Ex 25: 18th from right and 4th from right
Ans 25: Adding both the positions from right side, 18 and 4th , we get 18+4= 22; divide the same by 2 and we get 11. The 11th from right is 27-11= 16th from left i.e. ‘P’.
Ex 26: 15th from right and 16th from right